6x-0.06x^2=0

Solution for 6x-0.06x^2=0 equation:

6x-0.06x^2=0

a = -0.06; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-0.06)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-0.06}=\frac{-12}{-0.12}
=+100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-0.06}=\frac{0}{-0.12}
=0
$